SELECT e.*, s.salary, s.hourly_rate FROM employees AS e RIGHT JOIN salaries AS s ON s.employee = e.id WHERE 1 AND s.`` = '' AND e.`` = '' ORDER BY LIMIT ;
SELECT COUNT(DISTINCT e.id) as count FROM employees AS e RIGHT JOIN salaries AS s ON s.employee = e.id WHERE 1 AND e.`` = '' AND s.`` = '' LIMIT 1;
| Name | Agency | Class | Salary | OPS Hourly Rate |
|---|
SELECT date FROM data LIMIT 1;
Last time updated: April 2024.